[Solved] Given the code snippet:from flask_restx import Api, Namespace, Resource api = Api() users_ns = Namespace('users') @users_ns.route('/profile') class UserProfile(Resource): def get(self):... | Flask

Flask - WebSocket and Real-Time

Given the code snippet:

from flask_restx import Api, Namespace, Resource

api = Api()
users_ns = Namespace('users')

@users_ns.route('/profile')
class UserProfile(Resource):
    def get(self):
        return {'user': 'Alice'}

api.add_namespace(users_ns)

What URL path will return the JSON {'user': 'Alice'} when the Flask app runs?

A/api/users/profile

B/profile

C/users/profile

D/users

Step-by-Step Solution

Solution:

Step 1: Understand Namespace route prefix
The Namespace 'users' prefixes all routes inside it with '/users'. The route defined is '/profile'.
Step 2: Combine Namespace and route paths
Combining '/users' and '/profile' gives '/users/profile' as the full URL path.
Final Answer:
/users/profile -> Option C
Quick Check:
Namespace prefix + route = /users/profile [OK]

Quick Trick: Namespace name prefixes all its routes [OK]

Common Mistakes:

MISTAKES

Using route path without namespace prefix
Assuming '/api' prefix automatically added
Confusing route path with namespace name

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More Flask Quizzes

Given the code snippet:

Step 1: Understand Namespace route prefix

Step 2: Combine Namespace and route paths

Final Answer:

Quick Check:

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