[Solved] What is the issue with this Flask health check endpoint code?from flask import Flask, jsonify app = Flask(__name__) @app.route('/health') def health(): return jsonify({'status': 'ok'}) | Flask

Flask - Deployment

What is the issue with this Flask health check endpoint code?

from flask import Flask, jsonify
app = Flask(__name__)

@app.route('/health')
def health():
    return jsonify({'status': 'ok'})

AMissing return status code in the response

Bjsonify should be called with keyword arguments, not a dictionary

CThe route decorator is missing parentheses

DFlask app instance is not created properly

Step-by-Step Solution

Solution:

Step 1: Check usage of jsonify
jsonify expects keyword arguments or a list, not a dictionary as a single positional argument.
Step 2: Identify correct usage
Correct usage is jsonify(status='ok') instead of jsonify({'status': 'ok'}).
Final Answer:
jsonify should be called with keyword arguments, not a dictionary -> Option B
Quick Check:
Verify jsonify argument types [OK]

Quick Trick: jsonify accepts kwargs, not dict as single argument [OK]

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What is the issue with this Flask health check endpoint code?