[Solved] Given the following code, what will be the output when add.delay(4, 5) is called?... Given the following code, what will be the output when add.delay(4, 5) is called? | Flask

Flask - Background Tasks

Given the following code, what will be the output when add.delay(4, 5) is called?

from celery import Celery
celery_app = Celery('tasks')

@celery_app.task
def add(x, y):
    return x + y

result = add.delay(4, 5)
print(type(result))

A<class 'celery.result.AsyncResult'>

B<class 'int'>

C9

DNone

Step-by-Step Solution

Solution:

Step 1: Understand what delay() returns
The delay() method queues the task and returns an AsyncResult object, not the actual result.
Step 2: Check the printed type
Printing type(result) shows the class of the returned object, which is celery.result.AsyncResult.
Final Answer:
<class 'celery.result.AsyncResult'> -> Option A
Quick Check:
delay() returns AsyncResult object [OK]

Quick Trick: delay() returns AsyncResult, not the task output [OK]

Common Mistakes:

MISTAKES

Expecting delay() to return the task result immediately
Confusing AsyncResult with the actual return value
Printing result instead of type(result)

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More Flask Quizzes

Given the following code, what will be the output when add.delay(4, 5) is called?

Step 1: Understand what delay() returns

Step 2: Check the printed type

Final Answer:

Quick Check:

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