[Solved] Consider this FastAPI endpoint:from fastapi import FastAPI, UploadFile, File app = FastAPI() @app.post('/upload') async def upload(file: UploadFile = File(...)): content = await file.... | FastAPI

FastAPI - File Handling

Consider this FastAPI endpoint:

from fastapi import FastAPI, UploadFile, File
app = FastAPI()

@app.post('/upload')
async def upload(file: UploadFile = File(...)):
    content = await file.read()
    return {'name': file.filename, 'length': len(content)}

What will this endpoint return after a file upload?

AA JSON with the uploaded file's name and its size in bytes

BA JSON with the file's content as a string

CAn error because UploadFile cannot be read asynchronously

DA JSON with only the file's name but no size information

Step-by-Step Solution

Solution:

Step 1: Analyze the code
The endpoint reads the entire file asynchronously using await file.read().
Step 2: Understand the return statement
It returns a dictionary with the filename and the length of the content in bytes.
Final Answer:
A JSON with the uploaded file's name and its size in bytes -> Option A
Quick Check:
UploadFile.read() returns bytes; length gives size [OK]

Quick Trick: UploadFile.read() returns bytes; length is file size [OK]

Common Mistakes:

MISTAKES

Assuming file.read() returns a string instead of bytes
Thinking UploadFile cannot be read asynchronously

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Consider this FastAPI endpoint:

Step 1: Analyze the code

Step 2: Understand the return statement

Final Answer:

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