[Solved] Identify the error in this FastAPI code snippet for error handling:from fastapi import FastAPI, HTTPException app = FastAPI() @app.get("/items/{item_id}") async def read_item(item_id: int): if item_id | FastAPI

FastAPI - Error Handling

Identify the error in this FastAPI code snippet for error handling:

from fastapi import FastAPI, HTTPException
app = FastAPI()

@app.get("/items/{item_id}")
async def read_item(item_id: int):
    if item_id < 0:
        return HTTPException(status_code=400, detail="Invalid ID")
    return {"item_id": item_id}

AFunction should not be async

BMissing import for HTTPException

CShould use raise instead of return for HTTPException

DPath parameter should be a string, not int

Step-by-Step Solution

Solution:

Step 1: Check how HTTPException is used
HTTPException must be raised, not returned, to send an error response.
Step 2: Identify the mistake in code
The code returns HTTPException instead of raising it, so error handling won't work properly.
Final Answer:
Should use raise instead of return for HTTPException -> Option C
Quick Check:
Raise HTTPException, don't return it [OK]

Quick Trick: Use raise, not return, for HTTPException [OK]

Common Mistakes:

MISTAKES

Returning HTTPException instead of raising
Forgetting to import HTTPException
Wrong parameter types for path

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More FastAPI Quizzes

Identify the error in this FastAPI code snippet for error handling:

Step 1: Check how HTTPException is used

Step 2: Identify the mistake in code

Final Answer:

Quick Check:

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