[Solved] What will be the output of this code snippet? const expr = remove(['oldAttr']).toString(); Options:... What will be the output of this code snippet? | DynamoDB

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What will be the output of this code snippet? const expr = remove(['oldAttr']).toString(); Options: A) REMOVE oldAttr B) remove(oldAttr) C) REMOVE #oldAttr D) Error: remove() returns object, not string

AError: remove() returns object, not string

Bremove(oldAttr)

CREMOVE #oldAttr

DREMOVE oldAttr

Step-by-Step Solution

Solution:

Step 1: Understand remove() helper behavior
remove() builds a Remove expression starting with 'REMOVE' followed by attribute names.
Step 2: Check toString() output
Calling toString() returns the string 'REMOVE oldAttr' without attribute name placeholders.
Final Answer:
REMOVE oldAttr -> Option D
Quick Check:
remove() expression string = A [OK]

Quick Trick: remove() builds 'REMOVE' expressions; toString() returns string form [OK]

Common Mistakes:

MISTAKES

Assuming remove() returns an object only
Confusing attribute names with placeholders (#)
Using lowercase 'remove' in output

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What will be the output of this code snippet?

Step 1: Understand remove() helper behavior

Step 2: Check toString() output

Final Answer:

Quick Check:

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