[Solved] Given this code snippet, what will be printed when the message 'Hello everyone'... Given this code snippet, what will be printed when the message 'Hello everyone' is published to the chat channel? | Django

Django - Celery and Background Tasks

Given this code snippet, what will be printed when the message 'Hello everyone' is published to the chat channel?

import redis

r = redis.Redis()

pubsub = r.pubsub()
pubsub.subscribe('chat')

for message in pubsub.listen():
    if message['type'] == 'message':
        print(f"Received: {message['data'].decode()}")
        break

AReceived: Hello everyone

BReceived: message

CReceived: chat

DNo output, code will error

Step-by-Step Solution

Solution:

Step 1: Understand the subscription and listening
The code subscribes to 'chat' channel and listens for messages.
Step 2: Decode and print the message data
When a message is received, it decodes the bytes and prints with prefix 'Received:'.
Final Answer:
Received: Hello everyone -> Option A
Quick Check:
Message data decoded and printed [OK]

Quick Trick: Listen loop prints decoded message data on 'message' type [OK]

Common Mistakes:

MISTAKES

Printing message type instead of data
Not decoding bytes to string
Assuming code errors without message

Master "Celery and Background Tasks" in Django

9 interactive learning modes - each teaches the same concept differently

Learn Why Deep Visual Try Challenge Project Recall Perf

More Django Quizzes

Given this code snippet, what will be printed when the message 'Hello everyone' is published to the chat channel?

Step 1: Understand the subscription and listening

Step 2: Decode and print the message data

Final Answer:

Quick Check:

Want More Practice?