[Solved] Given this Django middleware snippet for error tracking:class ErrorLoggingMiddleware: def __init__(self, get_response): self.get_response = get_response def __call__(self, request): try:... | Django

Django - Deployment and Production

Given this Django middleware snippet for error tracking:

class ErrorLoggingMiddleware:
    def __init__(self, get_response):
        self.get_response = get_response

    def __call__(self, request):
        try:
            response = self.get_response(request)
        except Exception as e:
            log_error(e)
            raise
        return response

What will happen if an exception occurs during request processing?

AThe exception is logged by log_error and then re-raised

BThe exception is caught and suppressed silently

CThe middleware retries the request automatically

DThe middleware returns a default error response without logging

Step-by-Step Solution

Solution:

Step 1: Analyze the try-except block in middleware
The middleware tries to get the response. If an exception occurs, it calls log_error with the exception and then raises it again.
Step 2: Understand the effect of re-raising
Re-raising means the exception is not suppressed; it propagates up after logging.
Final Answer:
The exception is logged by log_error and then re-raised -> Option A
Quick Check:
Exception handling = log then re-raise [OK]

Quick Trick: Re-raise exceptions after logging to avoid silent failures [OK]

Common Mistakes:

MISTAKES

Assuming exceptions are suppressed
Thinking middleware retries requests
Believing default error response is returned

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More Django Quizzes

Given this Django middleware snippet for error tracking:

Step 1: Analyze the try-except block in middleware

Step 2: Understand the effect of re-raising

Final Answer:

Quick Check:

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