Given this code snippet, what will be printed when my_signal.send(sender=None, instance='obj1', created=True) is called?

medium📝 component behavior Q13 of 15

Django - Signals

Given this code snippet, what will be printed when my_signal.send(sender=None, instance='obj1', created=True) is called?

from django.dispatch import Signal, receiver

my_signal = Signal(providing_args=["instance", "created"])

@receiver(my_signal)
def my_receiver(sender, **kwargs):
    print(f"Received: {kwargs['instance']}, Created: {kwargs['created']}")

AReceived: obj1, Created: True

BReceived: None, Created: True

CReceived: obj1, Created: False

DError: missing sender argument

Step-by-Step Solution

Solution:

Step 1: Understand signal sending and receiver
The signal is sent with instance='obj1' and created=True. The receiver prints these values from kwargs.
Step 2: Match printed output to sent values
The print statement uses kwargs['instance'] and kwargs['created'], so it prints 'obj1' and 'True'.
Final Answer:
Received: obj1, Created: True -> Option A
Quick Check:
Signal send values print correctly [OK]

Quick Trick: Receiver prints kwargs values sent by signal [OK]

Common Mistakes:

MISTAKES

Confusing sender with instance
Assuming created is False by default
Thinking sender is required in print

Master "Signals" in Django

9 interactive learning modes - each teaches the same concept differently

Learn Why Deep Visual Try Challenge Project Recall Perf

Want More Practice?

15+ quiz questions · All difficulty levels · Free

Free Signup - Practice All Questions

More Django Quizzes

Given this code snippet, what will be printed when my_signal.send(sender=None, instance='obj1', created=True) is called?

Step 1: Understand signal sending and receiver

Step 2: Match printed output to sent values

Final Answer:

Quick Check:

Want More Practice?