You have a Celery task that calls another Celery task asynchronously inside it. What happens to the inner task when the outer task is called with delay()?

hard📝 Application Q9 of 15

Django - Celery and Background Tasks

You have a Celery task that calls another Celery task asynchronously inside it. What happens to the inner task when the outer task is called with delay()?

AThe outer task queues the inner task asynchronously, both run independently

BThe inner task runs synchronously inside the outer task

CThe inner task is ignored and never runs

DThe outer task waits for the inner task to finish before completing

Step-by-Step Solution

Solution:

Step 1: Understand nested async task calls
Calling delay() inside a task queues the inner task asynchronously, separate from the outer task.
Step 2: Confirm independence of tasks
Both tasks run independently; the outer task does not wait for the inner task to finish.
Final Answer:
The outer task queues the inner task asynchronously, both run independently -> Option A
Quick Check:
Nested delay() calls queue independent tasks [OK]

Quick Trick: delay() inside tasks queues new async tasks independently [OK]

Common Mistakes:

MISTAKES

Assuming inner task runs synchronously
Thinking outer task waits for inner task
Believing inner task is ignored

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More Django Quizzes

You have a Celery task that calls another Celery task asynchronously inside it. What happens to the inner task when the outer task is called with delay()?

Step 1: Understand nested async task calls

Step 2: Confirm independence of tasks

Final Answer:

Quick Check:

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