[Solved] Given this Celery task:@shared_task def multiply(x, y): return x * y What will result = multiply.delay(3, 4) return? | Django

Django - Celery and Background Tasks

Given this Celery task:

@shared_task
def multiply(x, y):
    return x * y

What will result = multiply.delay(3, 4) return?

AA syntax error because delay() is not valid

BAn AsyncResult object representing the task execution

CThe integer 12 immediately

DNone, because the task runs in background

Step-by-Step Solution

Solution:

Step 1: Understand what delay() returns
Calling delay() on a Celery task returns an AsyncResult object, not the task result immediately.
Step 2: Check other options
The task runs asynchronously, so the integer 12 is not returned immediately; no syntax error occurs; it does not return None.
Final Answer:
An AsyncResult object representing the task execution -> Option B
Quick Check:
delay() returns AsyncResult object [OK]

Quick Trick: delay() returns AsyncResult, not immediate result [OK]

Common Mistakes:

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