[Solved] What will be the output of this C# code?class Base { public virtual void Show() { Console.WriteLine("Base Show"); } } class Derived : Base { public override void Show() { Console.... | C Sharp (C#)

C Sharp (C#) - Inheritance

What will be the output of this C# code?

class Base { public virtual void Show() { Console.WriteLine("Base Show"); } } class Derived : Base { public override void Show() { Console.WriteLine("Derived Show"); } } class Program { static void Main() { Base b = new Derived(); b.Show(); } }

ADerived Show

BNo output

CCompilation error

DBase Show

Step-by-Step Solution

Solution:

Step 1: Understand virtual and override keywords
Base class method Show() is virtual, allowing Derived to override it with its own version.
Step 2: Analyze method call on Base reference
Though b is Base type, it points to Derived object, so Derived's Show() runs, printing "Derived Show".
Final Answer:
Derived Show -> Option A
Quick Check:
Virtual override calls derived method = "Derived Show" [OK]

Quick Trick: Virtual methods call derived override even via base reference [OK]

Common Mistakes:

MISTAKES

Expecting base method output when using base type variable
Confusing virtual and non-virtual methods
Thinking code causes compilation error

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What will be the output of this C# code?

Step 1: Understand virtual and override keywords

Step 2: Analyze method call on Base reference

Final Answer:

Quick Check:

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