[Solved] What will be the output of the following C# code?class Person { private string name = "Alice"; public string GetName() { return name; } } var p = new Person(); Console.WriteLine(p.GetName()); | C Sharp (C#)

C Sharp (C#) - Properties and Encapsulation

What will be the output of the following C# code?

class Person {
  private string name = "Alice";
  public string GetName() {
    return name;
  }
}

var p = new Person();
Console.WriteLine(p.GetName());

AAlice

Bname

CCompilation error

Dnull

Step-by-Step Solution

Solution:

Step 1: Understand private field and public method
The field name is private but accessible inside the class. The method GetName() returns the value of name.
Step 2: Check the output of calling GetName()
Calling p.GetName() returns "Alice", which is printed.
Final Answer:
Alice -> Option A
Quick Check:
Private field accessed via public method = Alice [OK]

Quick Trick: Private data accessed through public method returns actual value [OK]

Common Mistakes:

MISTAKES

Expecting a compilation error due to private field
Thinking it prints the field name 'name'
Assuming null because field is private

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More C Sharp (C#) Quizzes

What will be the output of the following C# code?

Step 1: Understand private field and public method

Step 2: Check the output of calling `GetName()`

Final Answer:

Quick Check:

Want More Practice?

What will be the output of the following C# code?

Step 1: Understand private field and public method

Step 2: Check the output of calling GetName()

Final Answer:

Quick Check:

Want More Practice?

Step 2: Check the output of calling `GetName()`