[Solved] What will be the output of this code snippet?try { throw new Exception("Test"); } catch (Exception ex) when (ex.Message == "Test") { Console.WriteLine("Caught with when");... | C Sharp (C#)

C Sharp (C#) - Exception Handling

What will be the output of this code snippet?

try {
    throw new Exception("Test");
} catch (Exception ex) when (ex.Message == "Test") {
    Console.WriteLine("Caught with when");
} catch (Exception) {
    Console.WriteLine("Caught without when");
}

ACaught with when

BCaught without when

CNo output, program crashes

DCompilation error

Step-by-Step Solution

Solution:

Step 1: Analyze the thrown exception and when condition
The exception message is "Test", matching the when condition ex.Message == "Test".
Step 2: Determine which catch block runs
The first catch block's when condition is true, so it handles the exception and prints "Caught with when".
Final Answer:
Caught with when -> Option A
Quick Check:
when true triggers catch = output printed [OK]

Quick Trick: when true runs catch block, else next catch tries [OK]

Common Mistakes:

MISTAKES

Ignoring when condition and picking second catch
Expecting program crash
Thinking when causes compile error

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More C Sharp (C#) Quizzes

What will be the output of this code snippet?

Step 1: Analyze the thrown exception and when condition

Step 2: Determine which catch block runs

Final Answer:

Quick Check:

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