[Solved] Identify the error in this C# string declaration:string s = @"Hello\nWorld"; - Ans: Escape sequences like \n are not processed in verbatim strings | C Sharp (C#)

C Sharp (C#) - Strings and StringBuilder

Identify the error in this C# string declaration:

string s = @"Hello\nWorld";

AEscape sequences like \n are not processed in verbatim strings

BNo error, this is correct verbatim string

CBackslash should be doubled as \\ in verbatim strings

DMissing semicolon at the end

Step-by-Step Solution

Solution:

Step 1: Understand verbatim string behavior
Verbatim strings treat backslashes literally and do not process escape sequences like \n.
Step 2: Analyze the given string
The string @"Hello\nWorld" will contain the characters \ and n literally, not a newline.
Final Answer:
Escape sequences like \n are not processed in verbatim strings -> Option A
Quick Check:
Verbatim strings ignore escape sequences = B [OK]

Quick Trick: Verbatim strings do not process escape sequences [OK]

Common Mistakes:

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