[Solved] Given this code, what will be the output? interface IA { void Show() => Console.WriteLine("IA"); } interface IB : IA { void Show() => Console.WriteLine("IB"); } class C :... | C Sharp (C#)

C Sharp (C#) - Interfaces

Given this code, what will be the output? interface IA { void Show() => Console.WriteLine("IA"); } interface IB : IA { void Show() => Console.WriteLine("IB"); } class C : IB { } class Program { static void Main() { IA a = new C(); IB b = new C(); a.Show(); b.Show(); } }

AIB IB

BIA IA

CIA IB

DCompile error

Step-by-Step Solution

Solution:

Step 1: Understand interface inheritance and default methods
IB inherits IA and overrides Show() with its own default method.
Step 2: Analyze calls via different interface references
Calling Show() via IA reference calls IA's default method; via IB reference calls IB's default method.
Final Answer:
IA IB -> Option C
Quick Check:
Interface reference calls respective default method = B [OK]

Quick Trick: Interface reference type decides default method called [OK]

Common Mistakes:

MISTAKES

Assuming class overrides default methods automatically
Expecting same output for both calls
Thinking compile error occurs due to multiple defaults

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Given this code, what will be the output?

Step 1: Understand interface inheritance and default methods

Step 2: Analyze calls via different interface references

Final Answer:

Quick Check:

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