[Solved] Identify the error in the following code snippet: int x; printf("Enter a number: "); scanf("%d", x); printf("You entered %d", x); | C

C - Input and Output

Identify the error in the following code snippet:

int x;
printf("Enter a number: ");
scanf("%d", x);
printf("You entered %d", x);

AMissing & before variable x in scanf

BWrong format specifier in scanf

CMissing semicolon after printf

DVariable x not declared

Step-by-Step Solution

Solution:

Step 1: Check scanf usage
scanf("%d", x); is incorrect because it should use &x to pass the address.
Step 2: Confirm other parts are correct
Format specifier is correct, semicolons are present, and x is declared.
Final Answer:
Missing & before variable x in scanf -> Option A
Quick Check:
scanf needs &variable for input [OK]

Quick Trick: Always use & before variables in scanf except arrays [OK]

Common Mistakes:

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