[Solved] What will be the output of the following commands?gcc -E file.c -o file.i gcc -S file.i -o file.s — Ans: file.i contains preprocessed code; file.s contains assembly code | C

C - Basics and Execution Environment

What will be the output of the following commands?

gcc -E file.c -o file.i
gcc -S file.i -o file.s

Afile.i contains object code; file.s contains executable

Bfile.i contains preprocessed code; file.s contains assembly code

Cfile.i contains source code; file.s contains preprocessed code

Dfile.i contains assembly code; file.s contains object code

Step-by-Step Solution

Solution:

Step 1: Analyze gcc -E command
'gcc -E' runs the preprocessor and outputs preprocessed source code to file.i.
Step 2: Analyze gcc -S command
'gcc -S' compiles source (here file.i) to assembly code, outputting file.s.
Final Answer:
file.i contains preprocessed code; file.s contains assembly code -> Option B
Quick Check:
Preprocessing = file.i, Assembly = file.s [OK]

Quick Trick: gcc -E outputs preprocessed code; gcc -S outputs assembly [OK]

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