[Solved] You have this script: #!/bin/bash set -e echo "Start" ls /nonexistent_directory echo "End" The script exits immediately after the ls command. How can you fix it to continue even if ls fails? | Bash Scripting

Bash Scripting - Error Handling

You have this script:

#!/bin/bash
set -e
echo "Start"
ls /nonexistent_directory
echo "End"

The script exits immediately after the ls command. How can you fix it to continue even if ls fails?

ARemove <code>set -e</code> from the script.

BAdd <code>|| true</code> after the <code>ls</code> command.

CChange <code>ls</code> to <code>ls -e</code>.

DAdd <code>set +e</code> at the start of the script.

Step-by-Step Solution

Solution:

Step 1: Understand why script exits
set -e causes the script to exit on any command failure, so ls /nonexistent_directory failing stops the script.
Step 2: Use || true to ignore error
Appending || true makes the command always succeed, preventing exit.
Final Answer:
Add || true after the ls command. -> Option B
Quick Check:
Use command || true to bypass set -e exit [OK]

Quick Trick: Add || true to ignore errors on specific commands [OK]

Common Mistakes:

MISTAKES

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