[Solved] You have a Bash array nums=(1 2 3 4 5). How do you print only the even numbers using a loop? - Ans: for n in "${nums[@]}"; do if (( n % 2 == 0 )); then echo $n; fi; done | Bash Scripting

Bash Scripting - Arrays

You have a Bash array nums=(1 2 3 4 5). How do you print only the even numbers using a loop?

Afor n in ${nums[@]}; do if [ $n % 2 -eq 0 ]; then echo $n; fi; done

Bfor n in "${nums[@]}"; do if [ $n % 2 == 0 ]; then echo $n; fi; done

Cfor n in "${nums[@]}"; do if (( n % 2 == 0 )); then echo $n; fi; done

Dfor n in ${nums[@]}; do if (( n % 2 )); then echo $n; fi; done

Step-by-Step Solution

Solution:

Step 1: Use correct arithmetic test syntax
Bash arithmetic evaluation uses (( )) and == for comparison.
Step 2: Loop over array with quotes to preserve elements
Using "${nums[@]}" ensures each number is treated correctly.
Final Answer:
for n in "${nums[@]}"; do if (( n % 2 == 0 )); then echo $n; fi; done -> Option C
Quick Check:
Use (( )) for arithmetic tests in Bash = B [OK]

Quick Trick: Use (( )) for math tests and quote arrays when looping [OK]

Common Mistakes:

MISTAKES

Master "Arrays" in Bash Scripting

9 interactive learning modes - each teaches the same concept differently

More Bash Scripting Quizzes

You have a Bash array nums=(1 2 3 4 5). How do you print only the even numbers using a loop?