How would you write a bash function total that sums all its numeric arguments and prints the result?

hard🚀 Application Q9 of 15

Bash Scripting - Functions

How would you write a bash function total that sums all its numeric arguments and prints the result?

Atotal() { sum=0; while read n; do sum=$((sum + n)); done; echo $sum; }

Btotal() { echo $(( $1 + $2 )); }

Ctotal() { let sum=$1+$2+$3; echo $sum; }

Dtotal() { sum=0; for n in "$@"; do sum=$((sum + n)); done; echo $sum; }

Step-by-Step Solution

Solution:

Step 1: Understand argument handling
To sum any number of arguments, iterate over all arguments using "$@".
Step 2: Accumulate sum
Initialize sum=0, then add each argument to sum inside a loop.
Step 3: Output the total
After the loop, print the sum.
Final Answer:
total() { sum=0; for n in "$@"; do sum=$((sum + n)); done; echo $sum; } -> Option D
Quick Check:
Loop over "$@" to handle all arguments [OK]

Quick Trick: Use for loop over "$@" to sum all arguments [OK]

Common Mistakes:

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