[Solved] Find the bug in this script:myarr=(1 2 3 4) len=${#myarr[@]} echo len - Ans: echo len prints the word 'len' instead of variable value | Bash Scripting

Bash Scripting - Arrays

Find the bug in this script:

myarr=(1 2 3 4)
len=${#myarr[@]}
echo len

ALength syntax is incorrect

BArray declaration is wrong

Cecho len prints the word 'len' instead of variable value

DNo bug, script works correctly

Step-by-Step Solution

Solution:

Step 1: Check echo command
echo len prints the literal string 'len', not the variable value.
Step 2: Correct usage
Use echo $len to print the value stored in variable len.
Final Answer:
echo len prints the word 'len' instead of variable value -> Option C
Quick Check:
Use $ before variable to print its value [OK]

Quick Trick: Use $ before variable name to print its value [OK]

Common Mistakes:

MISTAKES

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