You want to run a script that prints "Even" if a number is divisible by 2, otherwise "Odd". Which script correctly uses conditionals?

hard🚀 Application Q8 of 15

Bash Scripting - Conditionals

A#!/bin/bash num=4 if [ $(num % 2) -eq 0 ]; then echo "Even" else echo "Odd" fi

B#!/bin/bash num=4 if (( $num % 2 == 0 )); then echo "Even" else echo "Odd" fi

C#!/bin/bash num=4 if [ $num % 2 == 0 ]; then echo "Even" else echo "Odd" fi

D#!/bin/bash num=4 if [ $num / 2 -eq 0 ]; then echo "Even" else echo "Odd" fi

Step-by-Step Solution

Solution:

Step 1: Understand arithmetic evaluation in bash
Using (( )) allows arithmetic expressions and comparisons.
Step 2: Check each option's syntax
#!/bin/bash num=4 if (( $num % 2 == 0 )); then echo "Even" else echo "Odd" fi correctly uses (( $num % 2 == 0 )). #!/bin/bash num=4 if [ $((num % 2)) -eq 0 ]; then echo "Even" else echo "Odd" fi uses incorrect syntax inside [ ]. #!/bin/bash num=4 if [ $num % 2 == 0 ]; then echo "Even" else echo "Odd" fi uses invalid operator inside [ ]. #!/bin/bash num=4 if [ $num / 2 -eq 0 ]; then echo "Even" else echo "Odd" fi uses division instead of modulo.
Final Answer:
(( $num % 2 == 0 )) syntax -> Option B
Quick Check:
Use (( )) for arithmetic tests = C [OK]

Quick Trick: Use (( )) for math conditions in bash [OK]

Common Mistakes:

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