How to write a bash condition that prints "Valid" only if name is not empty and not equal to "admin"?

hard🚀 Application Q9 of 15

Bash Scripting - Conditionals

How to write a bash condition that prints "Valid" only if name is not empty and not equal to "admin"?

Aif [[ -z "$name" || "$name" = "admin" ]]; then echo "Valid"; fi

Bif [ -z "$name" -o "$name" = "admin" ]; then echo "Valid"; fi

Cif [[ -n "$name" && "$name" != "admin" ]]; then echo "Valid"; fi

Dif [ -n "$name" -a "$name" != "admin" ]; then echo "Valid"; fi

Step-by-Step Solution

Solution:

Step 1: Understand the condition
We want to print "Valid" if name is not empty AND not "admin".
Step 2: Analyze options
if [[ -n "$name" && "$name" != "admin" ]]; then echo "Valid"; fi uses [[ ]] with -n and && and quotes variables correctly. if [ -z "$name" -o "$name" = "admin" ]; then echo "Valid"; fi and C check opposite conditions. if [ -n "$name" -a "$name" != "admin" ]; then echo "Valid"; fi uses [ ] with -a which is less recommended.
Final Answer:
if [[ -n "$name" && "$name" != "admin" ]]; then echo "Valid"; fi -> Option C
Quick Check:
Use [[ ]] with -n and && for AND conditions [OK]

Quick Trick: Use [[ ]] with -n and && for AND string checks [OK]

Common Mistakes:

MISTAKES

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