You want to write a bash script that prints "Empty string" if variable text is empty, and "Has content" otherwise. Which snippet correctly does this?

hard🚀 Application Q15 of 15

Bash Scripting - Conditionals

You want to write a bash script that prints "Empty string" if variable text is empty, and "Has content" otherwise. Which snippet correctly does this?

Aif [ "$text" != "" ]; then echo "Empty string"; else echo "Has content"; fi

Bif [[ "$text" = "" ]]; then echo "Has content"; else echo "Empty string"; fi

Cif [ -n "$text" ]; then echo "Empty string"; else echo "Has content"; fi

Dif [[ -z "$text" ]]; then echo "Empty string"; else echo "Has content"; fi

Step-by-Step Solution

Solution:

Step 1: Understand -z usage
-z "$text" returns true if text is empty.
Step 2: Check echo outputs match condition
If empty, print "Empty string"; else print "Has content". if [[ -z "$text" ]]; then echo "Empty string"; else echo "Has content"; fi matches this logic correctly.
Final Answer:
if [[ -z "$text" ]]; then echo "Empty string"; else echo "Has content"; fi -> Option D
Quick Check:
-z empty -> print "Empty string" [OK]

Quick Trick: Use if [[ -z "$var" ]] for empty string check [OK]

Common Mistakes:

MISTAKES

Swapping outputs for empty and non-empty cases
Using = "" without quotes or wrong logic
Confusing -n and -z meanings

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More Bash Scripting Quizzes

You want to write a bash script that prints "Empty string" if variable text is empty, and "Has content" otherwise. Which snippet correctly does this?

Step 1: Understand -z usage

Step 2: Check echo outputs match condition

Final Answer:

Quick Check:

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