[Solved] What will be the output of this script?count=1 while :; do echo $count ((count++)) if [ $count -gt 3 ]; then break fi done | Bash Scripting

Bash Scripting - Loops

What will be the output of this script?

count=1
while :; do
  echo $count
  ((count++))
  if [ $count -gt 3 ]; then
    break
  fi
done

A1 2 3

B1 2 3 4

C1 2 3 4 5

DInfinite loop printing numbers

Step-by-Step Solution

Solution:

Step 1: Understand the loop condition
The loop uses while : which is an infinite loop, but it has a break condition inside.
Step 2: Trace the loop execution
It prints count starting at 1, increments count, and breaks when count > 3. So it prints 1, 2, 3 and stops before printing 4.
Final Answer:
1 2 3 -> Option A
Quick Check:
Break stops infinite loop at count 4 [OK]

Quick Trick: Break exits infinite loops early [OK]

Common Mistakes:

MISTAKES

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