Bash Scripting - Variables
Consider this script:
```bash
export VAR1=foo
VAR2=bar
bash -c 'echo "$VAR1 $VAR2"'
```
What is the output?
Consider this script: ```bash export VAR1=foo VAR2=bar bash -c 'echo "$VAR1 $VAR2"' ``` What is the output?
medium📝 Predict Output Q5 of 15
Step-by-Step Solution
Solution:
Step 1: Understand export effect
'VAR1' is exported, so it is available in the child bash process. 'VAR2' is not exported, so it is not available.Step 2: Analyze the child bash command
The child bash prints the values of VAR1 and VAR2. VAR1 prints 'foo', VAR2 is empty, so output is 'foo '.Final Answer:
foo -> Option BQuick Check:
Only exported variables appear in child processes [OK]
Quick Trick: Only exported variables pass to child shells [OK]
Common Mistakes:
MISTAKES- Assuming all variables pass to child processes
- Confusing export with assignment
- Expecting VAR2 to print 'bar'
Master "Variables" in Bash Scripting
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