Bash Scripting - Variables
What will be the output of the following script?
```bash
MYVAR=hello
function test_func() {
local MYVAR=world
echo "$MYVAR"
}
test_func
echo "$MYVAR"
```
What will be the output of the following script? ```bash MYVAR=hello function test_func() { local MYVAR=world echo "$MYVAR" } test_func echo "$MYVAR" ```
medium📝 Predict Output Q4 of 15
Step-by-Step Solution
Solution:
Step 1: Analyze variable inside function
Inside 'test_func', 'local MYVAR=world' creates a local variable 'MYVAR' with value 'world'. The echo prints 'world'.Step 2: Analyze variable outside function
Outside the function, 'MYVAR' remains 'hello' because the local variable inside the function does not affect it. The echo prints 'hello'.Final Answer:
world hello -> Option DQuick Check:
Local variables inside functions do not change global variables [OK]
Quick Trick: Local inside function hides global variable temporarily [OK]
Common Mistakes:
MISTAKES- Assuming local variable changes global variable
- Confusing output order
- Ignoring local keyword effect
Master "Variables" in Bash Scripting
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