You want to create a script that prints a message with a variable count inside double quotes, but only if count is not empty. Which is the best way to write this?

hard🚀 Application Q15 of 15

Bash Scripting - Quoting and Expansion

You want to create a script that prints a message with a variable count inside double quotes, but only if count is not empty. Which is the best way to write this?

Aif [ $count ]; then echo "Count is $count"; fi

Bif [ $count ]; then echo 'Count is $count'; fi

Cif [ "$count" ]; then echo "Count is $count"; fi

Dif [ "$count" ]; then echo 'Count is $count'; fi

Step-by-Step Solution

Solution:

Step 1: Check condition with quotes
Using [ "$count" ] safely tests if count is non-empty, even if it contains spaces or is unset.
Step 2: Print message with double quotes
Using double quotes in echo expands $count properly inside the string.
Final Answer:
if [ "$count" ]; then echo "Count is $count"; fi -> Option C
Quick Check:
Quote variables in tests and output for safety = D [OK]

Quick Trick: Quote variables in tests and output to avoid errors [OK]

Common Mistakes:

MISTAKES

Not quoting variable in test causing errors
Using single quotes in echo preventing expansion
Testing variable without quotes causing syntax errors

Master "Quoting and Expansion" in Bash Scripting

9 interactive learning modes - each teaches the same concept differently

Learn Why Deep Visual Try Challenge Project Recall Time

Want More Practice?

15+ quiz questions · All difficulty levels · Free

Free Signup - Practice All Questions

More Bash Scripting Quizzes

You want to create a script that prints a message with a variable count inside double quotes, but only if count is not empty. Which is the best way to write this?

Step 1: Check condition with quotes

Step 2: Print message with double quotes

Final Answer:

Quick Check:

Want More Practice?