[Solved] Why does this lazy loading route fail? { path: 'user', loadChildren: () => import('./user/user.module').then(m => m.UserModule) } UserModule is defined but the app throws a runtime error. | Angular

Angular - Performance Optimization

Why does this lazy loading route fail?

{ path: 'user', loadChildren: () => import('./user/user.module').then(m => m.UserModule) }

UserModule is defined but the app throws a runtime error.

AUserModule file path is incorrect

BThe path 'user' must be declared in AppModule imports

CloadChildren must return a component, not a module

DUserModule is missing RouterModule.forChild() imports for its routes

Step-by-Step Solution

Solution:

Step 1: Understand lazy loaded module routing
Lazy loaded modules must import RouterModule.forChild() with their routes.
Step 2: Identify cause of runtime error
If UserModule lacks RouterModule.forChild(), routing fails at runtime.
Final Answer:
UserModule is missing RouterModule.forChild() imports for its routes -> Option D
Quick Check:
Missing RouterModule.forChild() causes runtime routing error [OK]

Quick Trick: Lazy loaded modules need RouterModule.forChild() for routes [OK]

Common Mistakes:

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Why does this lazy loading route fail?