Agentic AI - Agent Safety and Guardrails
Which Python code snippet correctly determines if any banned word from the list
banned_words appears in the variable output?Which Python code snippet correctly determines if any banned word from the list banned_words appears in the variable output?
easy📝 Syntax Q3 of 15
Step-by-Step Solution
Solution:
Step 1: Understand the goal
We want to check if any word frombanned_wordsis present inoutput.Step 2: Analyze each option
- filtered = any(word in output for word in banned_words) uses
any()with a generator expression checking membership of each word inoutput, which is correct. - filtered = output in banned_words incorrectly checks if
outputis in the listbanned_words, which is the reverse. - filtered = banned_words in output checks if the entire list
banned_wordsis inoutput, which is invalid. - filtered = output.contains(banned_words) uses a non-existent method
containson a string.
- filtered = any(word in output for word in banned_words) uses
Final Answer:
filtered = any(word in output for word in banned_words) -> Option AQuick Check:
Check if any banned word is substring of output [OK]
Quick Trick: Use any() with a generator to check membership [OK]
Common Mistakes:
- Checking if output is in banned_words instead of the reverse
- Using invalid methods like contains() on strings
- Trying to check if the entire list is in the output string
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