[Solved] Find the error in this caching code and select the fix:cache = {} def get_result(x): if x in cache: return cache[x] result = compute(x) return result | Agentic AI

Agentic AI - Production Agent Architecture

Find the error in this caching code and select the fix:

cache = {}
def get_result(x):
    if x in cache:
        return cache[x]
    result = compute(x)
    return result

ARemove the cache dictionary entirely.

BChange 'if x in cache' to 'if x not in cache'.

CAdd 'cache[x] = result' before returning result.

DReturn 'cache[x]' without checking if key exists.

Step-by-Step Solution

Solution:

Step 1: Identify missing cache update
The function returns computed result but never saves it to cache, so caching fails.
Step 2: Fix by saving result in cache
Insert 'cache[x] = result' before returning to store computed value.
Final Answer:
Add 'cache[x] = result' before returning result. -> Option C
Quick Check:
Cache must store new results [OK]

Quick Trick: Always save new results to cache before returning [OK]

Common Mistakes:

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